Consider the isoelectronic series Sr 2+ , Y 3+ , Zr 4+ , Nb 5+ . Arrange these s

Question

Consider the isoelectronic series Sr2+, Y3+, Zr4+, Nb5+. Arrange these species as follows. (Use the appropriate <, =, or > symbol to separate substances in the list.)

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Consider the iso electronic series Sr2+, Y3+, Zr4+, Nb5+. Arrange these species as follows. (Use the appropriate symbol to separate substances in the list.) in order of increasing atomic or ionic radius in order of increasing ionization energy

Explanation / Answer

sr2+,Y3+, Zr4+ ,Nb5+
again all of these ions are isoelectronic with 36 electrons each so following the same concept.

number of protons for Sr2+ = 38..
number of protons for Y3+ = 39
number of protons for Zr4+ = 40
number of protons for Nb5+ = 41
so ionic radii decreases in the order :Sr2+> Y3+ > Zr4+ > Nb5+

Ionisation energy increases as we move towards right in periodic table so Sr2+> Y3+ > Zr4+ > Nb5+

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