Photons of light with an energy of 656 nm are being directed through a chamber o
ID: 821916 • Letter: P
Question
Photons of light with an energy of 656 nm are being directed through a chamber of hydrogen gas atoms. The gas atoms began in their ground state (ni=1).
What happens?
These photons of light pass through the chamber without affecting the gas.
All of the photons will be absorbed since they have a specific energy and electronic transitions are quantized.
Very few photons will be absorbed since there is not quite enough energy to have all of the electrons go from ni=1 to nf=2.
Photons with an energy of 656 nm are quite energetic. These photons will produce many different electronic energy transitions, e.g. ni=1 to nf=2 and ni=1 to nf=3 and ni=1 to nf=4, etc.).
These photons of light pass through the chamber without affecting the gas.
All of the photons will be absorbed since they have a specific energy and electronic transitions are quantized.
Very few photons will be absorbed since there is not quite enough energy to have all of the electrons go from ni=1 to nf=2.
Photons with an energy of 656 nm are quite energetic. These photons will produce many different electronic energy transitions, e.g. ni=1 to nf=2 and ni=1 to nf=3 and ni=1 to nf=4, etc.).
Explanation / Answer
Energy of photon=planks constant x speed of light / wavelength
6.626x10^-34 x 2.998x10^8 / 656x10^-9 = 3.02778x10^-19
? E = -1* RH( 1/nf^2 - 1/ni^2)
RH= 2.179 X 10-18 J Z= no.of electrons
=1*(-2.179 X 10-18 J)[1/4- 1/1] =1.63 X 10-18 J
since the energy of the photon is very less not even enough for one electron to move form ground state to excited state. It will just pass by the chamber without afffecting .
ans-A