Part A The activation energy of a certain reaction is 41.6 k J / m o l . At 25 ?
ID: 823464 • Letter: P
Question
Part A The activation energy of a certain reaction is 41.6kJ/mol . At 25 ?C , the rate constant is 0.0190s?1. At what temperature in degrees Celsius would this reaction go twice as fast?Part B Given that the initial rate constant is 0.0190s?1 at an initial temperature of 25 ?C , what would the rate constant be at a temperature of 100 ?C for the same reaction described in Part A? please help Part A The activation energy of a certain reaction is 41.6kJ/mol . At 25 ?C , the rate constant is 0.0190s?1. At what temperature in degrees Celsius would this reaction go twice as fast?
Part B Given that the initial rate constant is 0.0190s?1 at an initial temperature of 25 ?C , what would the rate constant be at a temperature of 100 ?C for the same reaction described in Part A? please help
Explanation / Answer
ln(k2/k1) = Ea/R(1/T1-1/T2)
=416000/8.314(1/298 -1/373)
ln(k2/k1)=-3.376