Please make the answers simple , thanks : In the above pairs of solutions, which
ID: 831515 • Letter: P
Question
Please make the answers simple , thanks :
In the above pairs of solutions, which has the higher osmotic pressure? How would you make 250. mL of a 4.4%W/v KBr solution in water? If 7.7 g of lithium iodide Is dissolved in enough water to make 400.0 mL of solution, what is the %w/v concentration? How would you prepare 2.0 L of a 1.06 M aqueous solution of potassiuin chloride? If you dissolve 0.440 g KSCN in enough water to make 340. mL of solution, what is the morality of the solution? If a 0.300 M glucose solution Is available for intravenous infusion, how many mL are needed to deliver 10.0 g of glucose? Some wines contain 0.010 M NaHS03 (sodium bisulfite) as a preservative. How many grams of NaHS03must be added to a 100. gal barrel of wine to reach this concentration? If you have a 12.0 M HCI stock solution, how would you prepare 300. mL of a 0.600 M HCI solution? How would you prepare 20.0 mL of a 0.10% w/v KOH solution from a 15%w/v KOH solution? Which of the following aqueous solutions would have the lowest freezing point? A) 6.2 M NaCI B) 2.1 M AI(N03)3 C) 4.3 M K2SO4 What is the osmolarity of a 3.3% w/v sodium phosphate solution? The osmolality of red blood cells Is 0.30 osmol. Which of the following solutions Is isotonio with red blood cells? A) 0.1 M Na,SO4 B) 1.0 M Na,S04 C) 0.2 M Na2SOdExplanation / Answer
25) 0.044 = x / 250 --> x = (0.044)(250) = 11 g
26) x = 7.7 / 400 = 0.01925 = 1.925%
27) M = mol / vol L --> 1.06M = x / 2.0 L --> x = (1.06M)(2L) = 2.12 mol. KCl weighs 74.5 grams per mole. So 2.12 * 74.5 = 157.94 grams of KCl needed to prepare.
28) KSCN weighs 97.2grams per mole. So 0.440 g / 97.2 = 0.005 mol and M = 0.005 mol / .340 L = 0.013M
29) .3 = (10 g / 180 g ) / x L --> x L = (0.056) / (0.3) = 0.19 L, so 190 mL
30) 0.010M = (x ) / (378.5 L*This is 100 galons converted*) --> x= 3.785 mol * 104g FW = 393.64g
31)(12M)(x mL)=(300mL)(0.6M) --> x mL = 15 mL
32) (.0010)(20) = (.15)(x) --> 0.13 mL, or 130 microliters
33)