If the position of equilibrium for the reaction H2SO3 + HPO42<=> HSO3- + H2PO4-
ID: 849584 • Letter: I
Question
If the position of equilibrium for the reaction H2SO3 + HPO42<=> HSO3- + H2PO4- lies far to the right, which statement below can be made concerning the acid-base strengths of the reacting components?
a) The position of equilibrium favors the stronger acid and base.
b) The acid H2SO3 is stronger than the acid H2PO4- and the base HPO42- is stronger than the base HSO3-.
c) The acid H2SO3 is stronger than the acid H2PO4- and the base HPO42- is weaker than the base HSO3-.
d) The weaker acid and weaker base reacted to produce their stronger conjugates.
Explanation / Answer
STATEMENT B is correct
because strong acid will produce weak conjugate base
since equilibrium lies towards right H2SO3 GIVING proton and form weak conjugate base HSO3- and HPO42- is weak acid so it happen to accept proton