Consider the following equilibrium reaction. N2(g) + 3H2(g) 2NH3(g) When the rea
ID: 852409 • Letter: C
Question
Consider the following equilibrium reaction. N2(g) + 3H2(g) 2NH3(g) When the reaction has reached equilibrium at 93 degree, the concentrations of the reactants and product are 0.318 M N2, 0.146 M H2, and 0.749 M NH3. Calculate the equilibrium constant (Kc) for this reaction at the same temperature. Did you remember how to write the equilibrium-constant expression for a given reaction? Did you recall that the concentrations of substances in an equilibrium reaction are expressed in units of molarity? For the reaction N2(g) + 3 H2(g) 2 NH3(g) at 25.0 degree, the Kc of the reaction is 5.4 times 105. Use the given concentrations to determine the following.Explanation / Answer
K = [NH3]^2 / [N2][H2]^3
K = (0.749)^2 /(0.318)*(0.146)^3
Kc = 566.863