Consider the reaction between aluminum sulfate and barium chloride shown. Which
ID: 860045 • Letter: C
Question
Consider the reaction between aluminum sulfate and barium chloride shown. Which of the statements is FALSE?
Al2(SO4)3 + 3 BaCl2 ? 3 BaSO4 + 2 AlCl3
the fact that the number of each type of atom on each side is equal is related to the Law of Conservation of Mass.
6 "molecules" of barium chloride will make 6 "molecules" of barium sulfate
aluminum chloride is a product of the reaction
this is neither a synthesis nor a decomposition reaction
there will be 3/2 times as many aluminum chloride molecules made as there are molecules of barium chloride used.
a.the fact that the number of each type of atom on each side is equal is related to the Law of Conservation of Mass.
b.6 "molecules" of barium chloride will make 6 "molecules" of barium sulfate
c.aluminum chloride is a product of the reaction
d.this is neither a synthesis nor a decomposition reaction
e.there will be 3/2 times as many aluminum chloride molecules made as there are molecules of barium chloride used.
Explanation / Answer
option E is wrong because correct statement is there will be 2/3 times as many aluminuium chloride molecules made as there are molecules of barium chloride used. because for 3 moles of barium chloride we get 2 moles of aluminuium chloride
3 moles of BaCl2 --------> 2 moles of AlCl3
1 mole of BaCl2 ----------> 2/3 moles of AlCl3