Can you please show me the steps on how you got your answer. Directions for the

Question

Can you please show me the steps on how you got your answer. Directions for the Equation Set: FOR QUESTIONS 1-4: Write and balance the symbolic equations. FOR QUESTION 5: Solve the stoichiometry completely. 1. aqueous sulfuric acid + aqueous potassium hydroxide _____________________________________________________________________________ 2. aqueous barium nitrate + aqueous sodium carbonate _____________________________________________________________________________ 3. solid sodium + water Can you please show me the steps on how you got your answer. Directions for the Equation Set: FOR QUESTIONS 1-4: Write and balance the symbolic equations. FOR QUESTION 5: Solve the stoichiometry completely. 1. aqueous sulfuric acid + aqueous potassium hydroxide _____________________________________________________________________________ 2. aqueous barium nitrate + aqueous sodium carbonate _____________________________________________________________________________ 3. solid sodium + water Can you please show me the steps on how you got your answer. Directions for the Equation Set: FOR QUESTIONS 1-4: Write and balance the symbolic equations. FOR QUESTION 5: Solve the stoichiometry completely. 1. aqueous sulfuric acid + aqueous potassium hydroxide _____________________________________________________________________________ 2. aqueous barium nitrate + aqueous sodium carbonate _____________________________________________________________________________ 3. solid sodium + water

Explanation / Answer

1) H2SO4(aq) + 2 KOH(aq) ---> K2SO4(aq) + 2 H2O(l)

2) Ba(NO3)2 (aq) + Na2CO3 (aq) ---> 2NaNO3 (aq) + BaCO3 (s)

3) 2Na (s) + 2H2O(l) --->2 NaOH(aq) + H2

4) 2 AgNO3 (aq) + Na2SO4 (aq) ---> Ag2SO4 (s) + 2 NaNO3 (aq)

5) NH4NO3 --> 2H2O(l) + N2O(g)

a) 1 mole of N2O at STP = 22.4L

o.5 mole =11.2 L of N2O

  b) 80 g of NH4NO3 will form H20 = 2x18g

4.1 g will form H2O = 36 x 4.1 /80 = 1.845 g

c) 18g 0f H2O have = 6.023 x 1023 molecules

1.845 g of H2O = 6.023 x 1023 x 1.845 / 18 = 0.617 x 1023 molecules

d) 80 g of NH4NO3 will form N20 = 44g

4,1g will form N2O = 44 x 4.1 /80 = 2.255g

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