Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Problem 16.63 Calculate the percent ionization of hydrazoic acid (HN3) in soluti

ID: 865051 • Letter: P

Question

Problem 16.63

Calculate the percent ionization of hydrazoic acid (HN3) in solutions of each of the following concentrations (Ka is given in Appendix D in the textbook).

Part A

0.374M .

Express your answer using two significant figures.

SubmitHintsMy AnswersGive UpReview Part

Correct

Part B

0.113M .

Express your answer using two significant figures.

0.71

SubmitHintsMy AnswersGive UpReview Part

Incorrect; Try Again; 3 attempts remaining

Part C

4.30

Problem 16.63

Calculate the percent ionization of hydrazoic acid (HN3) in solutions of each of the following concentrations (Ka is given in Appendix D in the textbook).

Part A

0.374M .

Express your answer using two significant figures.

SubmitHintsMy AnswersGive UpReview Part

Correct

Part B

0.113M .

Express your answer using two significant figures.

0.71

%

SubmitHintsMy AnswersGive UpReview Part

Incorrect; Try Again; 3 attempts remaining

Part C

4.30

Explanation / Answer

HN3 ----> H+ + N3-

0.374 - X...X.....X

pKa for HN3 = 4.6

Ka = 10^-pKa = 2.5 x 10^-5

2.5 x 10^-5 = X^2 / 0.374 - X

=> X = 3.06 x 10^-3 M

% ionization = X * 100 / Inital conc. of HN3 = 3.06 x 10^-3 x 100 / 0.374 = 0.82 %

B)

HN3 ----> H+ + N3-

0.113 - X...X.....X

Ka = 2.5 x 10^-5 = X^2 / 0.113 - X

=> X = 1.68 x 10^-3 M

% ionization = X * 100 / Inital conc. of HN3 = 1.68 x 10^-3 x 100 / 0.113 = 1.49 %

C)

HN3 ----> H+ + N3-

0.043 - X...X.....X

Ka = 2.5 x 10^-5 = X^2 / 0.043 - X

=> X = 1.037 x 10^-3 M

% ionization = X * 100 / Inital conc. of HN3 = 1.037 x 10^-3 x 100 / 0.043 = 2.41 %