Problem 16.63 Calculate the percent ionization of hydrazoic acid (HN3) in soluti
ID: 865051 • Letter: P
Question
Problem 16.63
Calculate the percent ionization of hydrazoic acid (HN3) in solutions of each of the following concentrations (Ka is given in Appendix D in the textbook).
Part A
0.374M .
Express your answer using two significant figures.
SubmitHintsMy AnswersGive UpReview Part
Correct
Part B
0.113M .
Express your answer using two significant figures.
0.71
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Incorrect; Try Again; 3 attempts remaining
Part C
4.30
Problem 16.63
Calculate the percent ionization of hydrazoic acid (HN3) in solutions of each of the following concentrations (Ka is given in Appendix D in the textbook).
Part A
0.374M .
Express your answer using two significant figures.
SubmitHintsMy AnswersGive UpReview Part
Correct
Part B
0.113M .
Express your answer using two significant figures.
0.71
%SubmitHintsMy AnswersGive UpReview Part
Incorrect; Try Again; 3 attempts remaining
Part C
4.30
Explanation / Answer
HN3 ----> H+ + N3-
0.374 - X...X.....X
pKa for HN3 = 4.6
Ka = 10^-pKa = 2.5 x 10^-5
2.5 x 10^-5 = X^2 / 0.374 - X
=> X = 3.06 x 10^-3 M
% ionization = X * 100 / Inital conc. of HN3 = 3.06 x 10^-3 x 100 / 0.374 = 0.82 %
B)
HN3 ----> H+ + N3-
0.113 - X...X.....X
Ka = 2.5 x 10^-5 = X^2 / 0.113 - X
=> X = 1.68 x 10^-3 M
% ionization = X * 100 / Inital conc. of HN3 = 1.68 x 10^-3 x 100 / 0.113 = 1.49 %
C)
HN3 ----> H+ + N3-
0.043 - X...X.....X
Ka = 2.5 x 10^-5 = X^2 / 0.043 - X
=> X = 1.037 x 10^-3 M
% ionization = X * 100 / Inital conc. of HN3 = 1.037 x 10^-3 x 100 / 0.043 = 2.41 %