Please explain your answer! (Just 52 and 53) If a reaction is zero-order in a re
ID: 868840 • Letter: P
Question
Please explain your answer! (Just 52 and 53)
If a reaction is zero-order in a reactant, when the concentration of the reactant is decreased by a factor of 2, the reaction rate will quadruple. decrease by a factor of 1/2. remain constant. decrease by a factor of 1/4. double. The radioactive nuclide 63Ni decays by a first-order process via the emission of a beta particle. The 63Ni nuclide has a half-life of 100. years. How long will it take for 71% of 63Ni to decay? The reaction 2H2(g) + 2NO(g) rightarrow 2H20(jr) + N2(s) IS first-order in H2 and second-order in NO at a particular temperature. What is the rate law?Explanation / Answer
51. In zero order reactio the rate of reaction does not depend upon the concentration of reactants so the rate of reaction will remain the same even on decreasing the cocentration by 2.
Option C
52. We know that
rate constatn = K = 0.693 / t1/2
so K = 0.693 / 100 = 6.93 X 10^-3 years-1
Now
ln A = - kt + ln Ao
A0 = 100
A = 100-71 = 29
So
ln 71 = -6.93 X 10^-3 X t + ln100
4.262= 6.93 X 10^-3 X t + 4.605
-0.343= =6.93 X 10^-3 X t
t = 49.49 years ( option C)
53.
Rate law is
Rate = K [H2] [NO]2
t =184.7 years