I need the answer for 10 When aqueous solutions of magnesium chloride and sodium
ID: 889855 • Letter: I
Question
I need the answer for 10 When aqueous solutions of magnesium chloride and sodium hydroxide are mixed, magnesium hydroxide precipitates out. Suppose that 100.0 m l of a 0.120 M solution of magnesium chloride is mixed with 100.0 mL of 0.210 M sodium hydroxide. How much magnesium hydroxide will be formed? Identify the element that is oxidized or reduced and indicate the substance which is acting as reducing agent and which substance is acting as oxidizing agent. 2Cu(s) + 8H (aq) rightarrow 3 Cu2(aq) + 2 NO(g) + 4H2O(1) Element that is oxidized is and its oxidation state is Element that is reduced is and its oxidation state is Oxidizing Agent Reducing Agent Mno2(s) + (aq) + H (aq) rightarrow a (NO ) (AQ) + C (S) Write balanced molecular, complete ionic, and net ionic equations for the following reactions. Aqueous solutions of barium bromide and silver nitrate, AgNO*, are mixed yielding a preoptate. ME: CE : NE: Aqueous solution of sulfuric add, H2SO2. is mixed with solution of barium nitrate H2SO4(aq) + Ba(OH)2(aq) rightarrow ME: CE:Explanation / Answer
Cu(s) from 0 (because it is elemental) --> Cu+2 (aq) has lost 2 electrons, therefore it is being OXIDIZED. Oxidation stante = 2
NO3- (has many oxygens) ---> NO(g) (has less oxygens) therefore its being REDUCED.
Oxidation state in reactant
NO3- = -1
O has -2 as charge, and there are 3 oxygens, therefore, -6
Charge of N should be -6+X = -1 ; X = +5
In product
O = -2, therefore N must have +2 (from +5 to +2, it is GAINING electrons)
Oxidizing agent (the one that is being reduced, and makes oxidation possible) NO3
Reducing agent (the onte that is being oxidized, makes reduciton possible) Cu
For
MnO2
Use same logic as before
MnO2 -->Mn2+
MnO2 = 0
+4 -4 = 0, here Mn has a charge of +4, then goes to +2, it is GAINING electrons, therefore, reducing. This is the oxidizing AGENT
For
I- --> I2
charge of I = -1 goes to charge = 0, because elemental form
I is LOSING electrons, therefore, OXIDIXING. This is a reduzing agent