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In a constant pressure calorimeter at standard conditions, 0.400 mol sodium meta

ID: 894981 • Letter: I

Question

In a constant pressure calorimeter at standard conditions, 0.400 mol sodium metal is reacted with 432.0mL of water as indicated in the following balanced equation:

The dry calorimeter apparatus has a total heat capacity of 678 J/C

The calorimiter, water and sodium metal all have an initial temperature of 25.20C and a final temperature of 34.20C

The aqueous solution that results has a total volume of 401.0 mL and a density of 1.04 g/mL

The aqueous solution has the same specific heat as pure water: 4.184 J/g*K

The calorimeter is perfectley insulated

Hint: Na is the limiting reactant

Explanation / Answer

Heat given out by reaction has raised the temperature of calorimeter and aqueous solution.
mass of water, mw = density * volume
                                 = 1.04 g/mL * 401 mL
                                 = 417.04 g
Q = Nc*(Tf-Ti) + mw*Cw*(Tf-Ti)
    = 678 * (34.2-25.2) + 417.04*4.184*(34.2-25.2)
     =21806 J
     = 21.81 KJ

0.4 mol Na gives 21.81 KJ of heat.
In reaction coefficient of Na =2
So, 2 mol will give : 21.81*2/0.4 = 109.1 KJ
deltar H = qp
so,.
delta H of reaction =109.1 KJ

To find delta U use:
delta H = delta U + ng*R*T
ng = numbe of moles of gases = 1 mol (2 mol of Na gives 1 mol of H2)
T = 34.2 oC = (34.2 + 273) K = 307.2 K
delta H = delta U + ng*R*T
109100 J = delta U + 1*8.314*307.2
delta U = 106500 J
     = 106.5 KJ