I just really want to learn how to solve this kind of problem. I know it involve
ID: 896663 • Letter: I
Question
I just really want to learn how to solve this kind of problem. I know it involves finding heat and work but I'm having a hard time trying to figure that out.
The picture wont upload so:
Sulfur dioxide, SO2(g), can react with oxygen to produce sulfur trioxide, SO3(g), by the following reaction
2SO2(g) + O2(g) --> 2SO3(g)
The standard enthalpies of formation for SO2(g) and SO3(g) are:
SO2(g) = -298.8 kj/mol
SO3(g) = -395.7 kj/mol
Calculate the amount of energy in the form of heat that is produced when a volume of 4.14 L of SO2(g) is converted to 4.14 L of SO3(g) according to this process at a constant pressure and temperature of 1.00 bar and 25.0 °C. Assume ideal gas behavior.
Explanation / Answer
Pressrue, P = 1 bar
Temperature T = 25'C = 298 K
Volume V = 4.14 L
Gas constant, R = 8.314*10-2 L bar K-1 mol-1
Using ideal gas constant, PV = nRT
n = PV/RT
Putting values we get :
n = 0.167 moles
Given reaction :
2SO2 (g) + O2(g) ----> 2SO3(g)
According to this reaction, heat produced = 2dHf(SO3)*n + dHf(O2) - 2dHf(SO2)*n
Here, n = number of moles = 0.167
dHf(O2) = standard enthalpy of formation of O2 = 0
Putting values we get :
Heat produced = 2*(-395.7)*0.167 + 0 - 2*(-298.8)*0.167 = -32.36 kJ
Thus, 32.36 kJ heat is consumed because sig is negative.