Part A If you purchase 4.11 mCi of sulfur 35, how many disintegrations per secon

Question

Part A If you purchase 4.11 mCi of sulfur 35, how many disintegrations per second does the sample undergo when it is brand new? Express in disintegrations per second??
Part B A 85.0 kg person is expose to 499 rad of radiation. How many joules did this person absorb? Express in joules Part A If you purchase 4.11 mCi of sulfur 35, how many disintegrations per second does the sample undergo when it is brand new? Express in disintegrations per second??
Part B A 85.0 kg person is expose to 499 rad of radiation. How many joules did this person absorb? Express in joules Part A Express in disintegrations per second??
Part B A 85.0 kg person is expose to 499 rad of radiation. How many joules did this person absorb? Express in joules

Explanation / Answer

part A)

we have 4.11 millicuries, which is 4.11 x 1 x 10^-3 x 3.7 x 10^10 = 1.52 x 10^8 disintegrations per second

so   it is 1.52 x 10^8 disintegrations per second

part B)

For the second, one rad = 0.01 joule/kg,

so we have:

85.0 kg x 0.01 J/rad x 499rad = 424 J

424 J this person absorb

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