I of a cation Formula of salt sample: Nac Trial 1 Trial 2 Mass of salt: 5.00 Mol

Question

I of a cation Formula of salt sample: Nac Trial 1 Trial 2 Mass of salt: 5.00 Moles of salt: Mass of water: 40.0 40.09 Initial temperature of salt and water: 4c243 C 24, 3°C Final temperature of salt and water: 23.G°c 236C Heat flow of water (include correct sign): Heat flow of salt (include correct sign): Enthalpy of solution for the salt: Enthalpy of formation of the salt: Enthalpy of formation of the anion: Enthalpy of formation of the cation: Average Enthalpy of formation of the cation: cation. Clearly show all calculations for the enthalpy of formation and average enthalpy of formation of the Include the summation of balanced chemical equations, similar to Example 8.3. Moles of Salt

Explanation / Answer

Heat flow of water = Q = m x Cp x dT

Trial 1 : 40g x 4.18J/g oC x (23.6-24.9) = -217.36J

Trial 2 : 40g x 4.18J/g oC x (23.6-24.3) = -117.04J

similarly, I need Cp of salt to calculate Q for salt

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