Part A: Standardization of the NaOH solution REPORT TABLE Trial 1 Trial 2 Mass o

Question

Part A: Standardization of the NaOH solution REPORT TABLE Trial 1 Trial 2 Mass of Oxalic Acid (g).60.% Moles of Oxalic Acid Moles of NaOH Initial burette reading (mL) 10.2 w 10.9mL Final burette reading (mL) 15 . a mL | 2a3 Volume of NaOH used (L) 15,m 28. 0.0157 O Molarity of NaOH Average molarity of NaOH Part B: Determining the Concentration of the HCI Solution Using the NaOH Solutiorn REPORT TABLE Volume of HCI(L)15m Trial 1 Trial 2 Initial burette reading (mL) Om 0.5mu Final burette reading (mL) Volume of NaOH used (L) 21.m 10,0224 2o.m | 25.0.0|25a Moles of NaOH Moles of HCI Molarity of HCl Avg. molarity of HCl

Explanation / Answer

its a acid base titration

so we need to use the method of equivalents for each experiment

N1V1= N2V2

n1M1V1 =n2M2V2

where n1 and n2 are no of acidic hydrogen and basic OH in acid and base respectively.

Use the above eauqtion for each experiment , the volume sof acid and base are given for different reaction so you will be able to calcualte

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---