Part B What is the enthalpy for reaction 1 reversed? reaction 1 reversed: N2O4N2

Question

Part B

What is the enthalpy for reaction 1 reversed?

reaction 1 reversed: N2O4N2 + 2O2

Express your answer numerically in kilojoules per mole

Part A

In the following experiment, a coffee-cup calorimeter containing 100 mLof H2O is used. The initial temperature of the calorimeter is 23.0 C. If 2.60 g of CaCl2 is added to the calorimeter, what will be the final temperature of the solution in the calorimeter? The heat of solution Hsoln of CaCl2 is 82.8 kJ/mol.

Express your answer with the appropriate units

Explanation / Answer

Part B

N2O4 ----> N2 + 2O2

delta H of the reaction = - delta Hf of N2O4 = -9.1 KJ

Therefore the delta H of the reverse reaction will be = 9.1 Kj

Part A

Moles of CaCL2 = 2.6/111 = 0.0234 moles

Now the delta H = -82.8 KJ/mol ) 0.0234 = -1.939 KJ

Therefore

Heat absorbed = Heat released

= 1.939 KJ = 100*1*4.134*(T-23)

= 1.939*1000 = 413.4*(T-23)

=T = 27.69 degree celsius

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