Problem 7.5 Consider the A2X4 molecule depicted below, where A and X are element

Question

Problem 7.5

Consider the A2X4 molecule depicted below, where A and X are elements. The AA bond length in this molecule is d1, and the four AX bond lengths are each d2.(Figure 1)

Part A

In terms of d1 and d2, how could you define the bonding atomic radius of atom A?

Express your answer in terms of the variables d1 and d2.

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Part B

In terms of d1 and d2, how could you define the bonding atomic radius of atom X?

Express your answer in terms of the variables d1 and d2.

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Part C

In terms of d1 and d2, what would you predict for the XX bond length of an X2 molecule?

Express your answer in terms of the variables d1 and d2.

Problem 7.5

Consider the A2X4 molecule depicted below, where A and X are elements. The AA bond length in this molecule is d1, and the four AX bond lengths are each d2.(Figure 1)

Part A

In terms of d1 and d2, how could you define the bonding atomic radius of atom A?

Express your answer in terms of the variables d1 and d2.

rA =

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Part B

In terms of d1 and d2, how could you define the bonding atomic radius of atom X?

Express your answer in terms of the variables d1 and d2.

rX =

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Part C

In terms of d1 and d2, what would you predict for the XX bond length of an X2 molecule?

Express your answer in terms of the variables d1 and d2.

rXX =

Explanation / Answer

Solution :-

Parr A

In terms of d1 and d2, how could you define the bonding atomic radius of atom A?

Solution :-

rA = d1/2              because the radoius of the A is the half of the bond length of the A-A

   

Part B

In terms of d1 and d2, how could you define the bonding atomic radius of atom X?

Solution :-

Distance d2 is the sum of the radius of the A and X

Therefore , rA+rX

We know that rA = d1/2

Therefore

d2 = rX+(d1/2)

therefore

rX= d2 – (d1/2)

Part C

In terms of d1 and d2, what would you predict for the XX bond length of an X2 molecule?

Solution :-

The bond length of the X-X bond is the sum of the radius of the X atoms therefore

2rX = 2(d2-(d1/2)

       =2d2 – d1

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