Convert the following potentials. The Ag | AgCl and calomel reference electrodes
ID: 924422 • Letter: C
Question
Convert the following potentials. The Ag | AgCl and calomel reference electrodes are saturated with KCl. (Use this figure.) (a) 0.516 V versus S.H.E. = ? versus Ag | AgCl WebAssign will check your answer for the correct number of significant figures. V (b) -0.110 V versus Ag | AgCl = ? versus S.H.E. WebAssign will check your answer for the correct number of significant figures. V (c) -0.219 V versus S.C.E. = ? versus S.H.E. WebAssign will check your answer for the correct number of significant figures. V (d) 0.023 V versus Ag | AgCl = ? versus S.C.E. WebAssign will check your answer for the correct number of significant figures. V (e) -0.023 V versus S.C.E. = ? versus Ag | AgCl
Explanation / Answer
S.H.E. potential is equal to 0.0V
S.C.E. Potential is equal to +0.241
(a) 0.516 V versus S.H.E. =0.516-0=0.516V
whereas Ag/ AgCl electrode potential is =0.197 V
So the potential required is=0.516-0.197=0.319V versus Ag | AgCl
(b) -0.110 V versus Ag | AgCl =-0.110+0.197=0.0897 versus SHE
(C) -0.219 V versus S.C.E. = -0.219V+0.241=0.022V
(d) 0.023 V versus Ag | AgCl = 0.023+0.197= 0.22 versus S.H.E.
S.C.E. potential is 0.241V so 0.220-0.241=-0.021 versus S.C.E
0.023 V versus Ag | AgCl= -0.021 versus S.C.E
(e) -0.023 V versus S.C.E =-0.023+0.241=0.218V versus S.H.E.
Ag | AgCl =0.197V so 0.218-0.197=0.021V
-0.023 V versus S.C.E = 0.021V versus Ag | AgCl