Consider the voltaic cell below, which is symmetric except for the fact that [Cu
ID: 934076 • Letter: C
Question
Consider the voltaic cell below, which is symmetric except for the fact that [Cu2+] = 1.0 M on the left side and [Cu2+] = 0.01 M on the right. Both electrodes consist of a Cu electrode immersed in an aqueous Cu2+ solutioWhich electrode is positive, and what is Ecell?Cu/Cu2+, 1 M/Cu2+, 0.01 M/C
Left electrode is positive, and Ecell = 0.059 V
B) Right electrode is positive, and Ecell = 0.059 V
C) Left electrode is positive, and Ecell = 0.118 V
D) Right electrode is positive, and Ecell = 0.030 V
E) Right electrode is positive, and Ecell = 0.118 V
Explanation / Answer
Let us take the cell as given Cu/Cu+2(1M)|| Cu+2(0.01M)/Cu
Lets write the cell reaction Cu -----Cu+2(1M) oxidation (negative)
Cu+2(0.01M) ---Cu reduction (positive)
Cell reaction Cu+2(0.01M) ----- Cu+2(1M)
Using Nernst equation
Ecell = Eo