Conduct metric Titration of H_2(SO_4) and Ba(OH)_2 Write an equation (including
ID: 939898 • Letter: C
Question
Conduct metric Titration of H_2(SO_4) and Ba(OH)_2 Write an equation (including states of matter) for the reaction between H_2(SO_4) and Ba(OH)_2 At the very start of the titration, before any titrant has been added to the beaker, what is present in the solution? What is the conducting species in this initial solution? Describe what happens as titrant is added to the beaker. Why does the conductivity of the solution decrease? What is the identity of the solid formed? What is the conducting species present in the beaker? What happens when the conductivity value reaches its minimum value (which is designated as the equivalence point for this type of titration)? What is the conducting species in the beaker? Describe what happens at additional titrant is added past the equivalence point. Why does the conductivity of the solution increase? What is the conducting species present in the beaker?Explanation / Answer
1. Chemical equation : Ba(OH)2(aq) + H2SO4(aq) ---> BaSO4(s) + 2H2O(l)
2. At the begining of titration species present in beaker would be Ba2+ and OH-
3. When the titrant is added to the beaker,
a. More of BaSO4(s) is formed, which reduces the amount of Ba2+ and OH- concentration in solution. The conductivity which is dependent upon number of ree ions in solution ths decreases. We had 3 ions in Ba(OH)2 and we have moved to 2 ions in BaSO4.
b. The solid formed : BaSO4
c. Conducting species : Ba2+, OH-
3. At the equivalence point the conducting solution has, Ba2+ and SO4^2- at very low concentration.
4. When additional titrant is added,
a. more of H2SO4 gets dissociated into H+ and HSO4- ions, which increase the conductivity of the solution.
b. The species present are H+, HSO4- and some Ba2+ and SO4^2-