Assuming that 2.2 million metric tons of adipic acid will be synthesized yearly

Question

Assuming that 2.2 million metric tons of adipic acid will be synthesized yearly by industrial nitric acid oxidation, and that for every mole of adipic acid produced, a mole of N,_2Owill be emitted into the atmosphere, calculate the number of moles and mass of N_2O that will be released into the atmosphere each year from nylon synthesis. As shown in the reaction equation for this experiment, each mole of cyclohexene reacts with four moles of H_2O_2 to give adipic acid. You added about 3.6 grams of H_2O_2 to your reaction mixture (12 grams of a 30% solution were added). Calculate the mass of H_2O-2 required to react with 2.00 g of cyclohexene. How does this result relate to the principle of atom economy? Nylon, a polyamide, is produced from hexanediamine and a substance X. This substance X is most probably an amine. a carboxylic acid. a nitrile. an alcohol.

Explanation / Answer

First calculate the number of adipic acid in 2.2 million metric ton as follows:

A metric unit of weight equal to one thousandth of a kilogram

1 Metric Ton = 1 000 000 Grams

2.2 million metric ton = 1 000 000 Grams/1 Metric Ton*2.2 Metric Ton

= 2200000. G

Molar mass of adipic acid = 146.1412 g/mol

Number of mole of adipic acid = 2200000. g/146.1412 g/mol

= 15053.9 mol

Given that one mole of adipic acid emit one mole of N2O thus the number of moles of adipic acid is 15053.9 mol.

Now convert it into mass as follows:

15053.9 mol* molar mass of N2O

15053.9 mol*44.013 g/mol

=6625668.8 g

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