Part A.) The net ionic equation for the reaction between aqueous solutions of Li

Question

Part A.)The net ionic equation for the reaction between aqueous solutions of Li2CO3 and CaCl2 is ______?

2Li+(aq) + CO32-(aq) --> Li2CO3

2Li+(aq) + 2Cl-(aq) -->2LiCl(aq)

Li+(aq) + Cl-(aq) --> LiCl(aq)

Ca2+(aq) + CO32- (aq) --> CaCO3

there is no reaction when these solutions are combined

Part B.) Sulfur and fluorine react in a combination reaction to produce sulfur hexafluoride:

S + 3 F2 ---> SF6

You place 3.5 g sulfur and 4.5 g fluorine in a reaction flask.

The maximum amount of SF6 that can be produced from the reaction is __________ g.

Part C.) In the following reaction what is the oxidizing agent?

4 Na(s) + O2(g) --> 2 Na2O(s)

Na

O2

Na2O

NaCl

This is NOT a redox reaction

Na

O2

Na2O

NaCl

This is NOT a redox reaction

Explanation / Answer

Part A Ca2+(aq) + CO32- (aq) --> CaCO3

Part B

3.5 g sulfur = 3.5 /32 = 0.1094 Mole

4.5 g fluorine = 4.5 /18.99 = 0.2369 Mole

4.5 g fluorine is limiting reagent. Hence 0.2369 Mole of fluorine will produce (0.2369 /6) 0.0394944 mole of SF6.

0.0394944 mole of SF6 = 0.0394944 x 146.06 = 5.768 gm of SF6 will Produce.

Part C.) oxidizing agent is O2

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