Here is the answer of question 1. I need the answer of question 2 please. o AT&T
ID: 950224 • Letter: H
Question
Here is the answer of question 1. I need the answer of question 2 please.o AT&T; 7:15 PM 24oesof//eede." awalys.s # Variables Cjh4C4%.-K, rces wot react;species bala"ces 0 - most commo n for this process OA C3H6 + C6H6 GH 12 In an undesired side reaction, cumene can react with propylene to form p- diisopropylbenzene (p-DIPB) (25 pts) Draw and label a flowchart of the process and do the degrees-of-freedom analysis based on atomic species balances, taking a basis of 100 mol C9H12 produced. Assume that the feed contains only propylene and benzene, and that all of the propylene is consumed in the reaction. 1, (75 pts) The reactor is designed to yield a 20% conversion of benzene and a selectivity of 10 mol C9H12/mol C12H13 with a negligible amount of propylene in the product gas. Calculate the feed ratio (mol C6H6/mol C3H6) and the fractional yield of 2
Explanation / Answer
The conversion with respect to benzene is 20% which means that only 20% of the benzene in the feed is converted now the amount of propylene in the feed will have to be limiting as all the propylene is consumed such that we get cumene to DIPB in the ratio of 10:1
So propylene consumed is 10 for cume and 2 for DIPB
so for every 12 moles of propylene consumed 11 moles of benzene is consumed (10 for cumene and 1 for DIPB)
so if 100% benzene was to be consumed the ratio of propylene to benzene in the feed should have been 12 moles of propylene and 11 moles of benzene. But since 20% benzene is consumed we need to have the feed to benzene to be such that the 11 moles consumed is only 20% of the total in the feed.
So the feed should have 11moles /0.2 = 55 moles of benzene should be in the feed when 12 moles of propylene are present.
So feed ratio should be 55 moles C6H6/12 moles C3H6 = 4.58
Fractional yield of cumene will be 10 moles of cumene will be 10 moles x 120.20 g/mol = 1202 g cumene
1 mole of DIPB will be 162.27 g/mol = 162.3 g
1202g/(1202+162.3) = 0.881 is the fractional yield of cumene