How many moles of HCl did you add to fully neutralize the Na 2 CO 3 solution? Ex
ID: 954846 • Letter: H
Question
How many moles of HCl did you add to fully neutralize the Na2CO3 solution?
Experiment 3: Isolate Sodium Chloride
Lab Results
Record the following masses:
Data Analysis
Convert the mass of NaCl to moles, given its molar mass (MM) of 58.443 g/mol.
Conclusions
Calculate the experimentally determined molar ratio of Na2CO3 to NaCl using the formula below.
molar ratio = (mol Na2CO3) / (mol NaCl)
Use the theoretical molar ratio to calculate the theoretical yield of NaCl in grams from 2.000 g of Na2CO3?
The percent yield is the ratio of the actual amount of a product to the theoretical amount. Calculate the percent yield of NaCl as shown below.
%yield = (experimental yield) / (theoretical yield) × 100
Given the data below, how many grams of CO2 would you expect to be formed in the reaction of excess HCl with the Na2CO3?
Explanation / Answer
Na2CO3 + 2 HCl = 2 NaCl + H2O + CO2
theoretical yield of NaCl (2.000 g of Na2CO3) = 2.20 gm
Grams of CO2 would expect to be formed in the reaction (2.375g Na2CO3) = 0.9861 gm