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Please solve all parts of this problem and show your steps. I will rate your res

ID: 963654 • Letter: P

Question

Please solve all parts of this problem and show your steps. I will rate your response .

Thanks

(7%) Problem 10: Consider a process that uses 71 moles of a monatomic ideal gas operating through a Carnot cycle. The initial temperature and pressure ofthe gas are T1 and P1, respectively. Consider steps 1-2, 2 3. 3 4, and 4-1 P P,V,T, Otheexpertta.com 14% Part(a) Select the correct answers for the isothermal and adiabatic steps 14% Part (b) Write an expression for ly in terms of n, R. T1, and P1 14% Part (c) In the isothermal compression the gas is reduced to one-fourth its original volume. Write an expression for the pressure P2 in terms of P, after this step 14% Part (d) In the adiabatic heating the temperature of the gas is doubled. Write an expression for the volume l 3 after this step in terms of V1 Grade Summary 0% 100% Potential Submissions Attempts remainng: 5 % per attempt) detailed view Submit I give up! Hints: 4 for a 0% deduction. Hits remaing: ( Hints remaining: Feedback: 0% deduction per feedback. -Use the information from the problem to determine the temperature I3 in terms of I Use the relationship between T and V for a monatomic ideal gas in an adiabatic step to determine 13. (You will need to relate T3·1, T., and T2). -Recall that, for a monatomic ideal gas, the relationship between the constant pressure and constant volume heat capacities is G, / cv-5: 3 -Recall that r, = r, /4 Submission History Hints Feedback Totals 0% Answer Totals 0% 0% 14% Part (e) Write an expression for P3 in terms of n, R, T3 and V3 14% Part (f) Write an expression for the volume V4 in terms of V1 14% Part (g) Write an expression for P4 in terms of n, R. T4 and

Explanation / Answer

a)3-->4 - isothermal expansion delta T =0

4-->1 - adiabatic q=0

1---->2 -isothermal compression

2---> 4 - adiabatic q =0

b - P1V1 =nRT1

V1= nRT1/P1

c- PV=nRT

V2= V1/2

T1=T2 n and R= constant

so P1V1/P2V1/2 =nRT1/nRT2

So, P2 = 2P1