Part A If 32 mL of 6.8 M H2SO4 was spilled, what is the minimum mass of NaHCO3 t

Question

Part A
If 32 mL of 6.8 M H2SO4 was spilled, what is the minimum mass of NaHCO3 that must be added to the spill to neutralize the acid?
Express your answer using two significant figures.

Question 13 Some sulfuric acid is spilled on a lab bench. You can neutralize the acid by sprinkling sodium bicarbonate on it and then mopping up the resultant solution. The sodium bicarbonate reacts with sulfuric acid as follows: 2NaHCO3 (s) + H2SO4 (aq) Na2SO4 (aq) 2H2O(1) +2CO2 (9) Sodium bicarbonate is added until the fizzing due to the formation of CO2(g) stops.

Explanation / Answer

mmol of acid = MV = 32*6.8 = 217.6 mmol of acid

ratio is 2:1

so we need

217.6*2 = 435.2 mmol of NaHCO3

mass = mol*MW = (435.2*10^-3) (84.007 ) =36.5598 g of NaHCO3 required

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