Identify the oxidized substance, the reduced substance, the oxidizing agent, and
ID: 974559 • Letter: I
Question
Identify the oxidized substance, the reduced substance, the oxidizing agent, and the reducing agent in the following redox reaction: 3Ni^2*(aq) + 2CO(s) rightarrow 2 Co^3+ (aq) + 3 Ni (s) Carrier concentration in solid and mobilit) |20 pl| Assume n-type extrinsic silicon doped with 6 times 10^17 cm^-3 donors (i.e. Arsenide. As). (a) What's the hole concentration p0 at T= 300 K? (b) What's E_F relative to E_1? (c) Once you know the carrier concentration, you may use the follow ing figure to evaluate the mobility. Please estimate the conductivity of this n-type silicon.Explanation / Answer
The total reaction is:
3Ni+2(aq) + 2 Co (s) ....> 2Co+3(aq) + 3 Ni(s)
and the half reactions are:
Ni+2(aq) + 2e- -----> Ni(s) Eq.1
Co ------> Co+3(aq) + 3e- Eq.2
To equilibrate the electrons, you have to nultiply Eq.1 x 3 and Eq.2 x 2, as follows:
3 x (Ni+2(aq) + 2e- -----> Ni(s)) Gain of electros: Reduction. Catode.
2 x (Co ------> Co+3(aq) + 3e- ) Loss of electros: Oxidation. Anode.
And the total reaction is:
3Ni+2(aq) + 2 Co (s) ....> 2Co+3(aq) + 3 Ni(s)
Ni+2 gains electrons and because of that it gets reduced and it is an oxidant agent.
Co loss electrons and it gets oxidized. The it is the reducing agent:
Summary:
Which substance gets oxidized?..... Co
Which substance gets reduced?..... Ni+2
What is the oxidizing agent?...........Ni+2
What is the reducing agent?...........Co