Map sapling learning If you were going to graphically determine the activation e

Question

Map sapling learning If you were going to graphically determine the activation energy of this reaction, what points would you plot? Consider this reaction data: A products Number Number T (K) k (s) 225 775 point 10.004 0.989 To avoid rounding errors, use at least three significant fiqures in all values. 0.372 0.735 Number Number point 2: 0.001 0.308 Determine the rise, run, and slope of the line formed by these points rise run slope Number Number Number 0.681 0.003 215.9 What is the activation energy of this reaction? Number 1887.28 J/ mol Previous 8) Give Up & View Solution Try Again Next Exit Explanation

Explanation / Answer

since K= Ko*e-Ea/RT

lnk= lnK0- Ea/RT

K0= frequency factor

a plot of lnK vs 1/T gives a striaght line. Hence 1/T has to be on x axis and lnK on y axis

for the first poinnt T is 225 and 1/T= 0.00444   and lnK= ln (0.372)=-0.9888

for the second point T is 775 1/T= 1/775=0.00129 and ln K= ln (0.735)= -0.30788

slope= = -(0.9888-0.30788)/(0.00444-0.00129)=-215.9

-Ea/R= slope where E = activation energy and R= 8.314 j/mole.K ( gas constant)

Ea= 215.9*8.314 =1795 joules/mole

rise= different in y axis= 0.6809 and run= 0.00444-0.0129=0.003154

2.slow step will be rate determining step

Hence rate K[B][C], where K is rate constant

for the first reaction K1[A]2-K2[B]= 0 since equilibrium reaction

K1 and K2 are rate constnat for the forward and backward reaction

[B] = K1[A]2/ K2 and rate of reaction= K1*K1 [A]2 [C]/ K2

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