Map sapling leaning pylinder which is in a horizontal position contains an unkno
ID: 1481437 • Letter: M
Question
Map sapling leaning pylinder which is in a horizontal position contains an unknown noble gas at 4.42 x 104 Pa and is sealed with a massless piston. The piston is slowly, isobarically moved inward 0.176 m, while 1.95 x104 J of heat is removed from the gas. If the piston has a radius of 0.327 m, calculate the change in internal energy of the system. Incorrect. It seems like you may have confused the "sign" of the heat and work. Heat is being removed from the gas and work is being added to the gas Number u-112.21× 104 Previous Give Up & View Solution # Try Again O Next HExiExplanation / Answer
P =4.42x10^4 pa, h =0.176 m , r =0.327 m
In isobaric process pressure is constant.
W = PDV = - P(pi*r2*h)
W = -(4.42x104)(3.14x0.327x0.327x0.176)
W = -0.26x104 J
amount of heat remove from gas Q = -1.95x10^4 J
From first law of thermodynamics
Q =DU +W
DU =Q-W = (-1.95x104)+(0.26x104)
DU = -1.69x104 J
Change in internal energy of system = 1.69x104 J