Two animals of similar weight (100kg) begin preparations for winter hibernation.
ID: 983123 • Letter: T
Question
Two animals of similar weight (100kg) begin preparations for winter hibernation. In order to survive the winter, the animals must store 1000 kilocalories of energy in their bodies for each day of hibernation; they hibernate for 90 days. Animal 1 can only store energy in the form of carbohydrates (~4 kcal/g), whereas animal 2 can only store energy in the form of fats (~8 kcal/g). Assuming each animal meets the minimum energy storage requirement, calculate the weights of these animals (in kg) at the start of hibernation.
Explanation / Answer
Animal 1 Start with 100Kg, to store 1000kcal/4kcal/g= 250g. Animal 1 weight before hibernation 100.250g
Animal 2 Start with 100Kg, to store 1000kcal/8kcal/g= 125g Animal 2 weight before hibernation 100.125g