I need help with this question and i have no idea where to start, any help would

Question

I need help with this question and i have no idea where to start, any help would be appreciated.

The equilibrium constant, K, of a certain first order reaction was measured at two If you were going to graphically determine the enthalpy r, for this reaction, what points would you plot? temperatues, T The data is shown in this table Number Number T(K)K 275 725 To avoid rounding errors, use three significant figures in the x values and four significant figures in the y values. point 1 3.07 5.55 Number Number point 2: Determine the rise, run, and slope of the line formed by these points ise run slope Number Number Number What is the standard enthalpy of this reaction? Number J/ mol

Explanation / Answer

Given data :

T(K)     K

275     3.07

725     5.55

For plot,

                         x (1/T)                       y (lnK)

Point 1 :         0.0036364                   1.1217

Point 2 :        0.0013793                    1.7138

Determination of rise, run and slope

rise = y2-y1 = 1.7138 - 1.1217 = 0.5921

run = 0.0013793 - 0.0036364 = -0.0022571

slope = rise/run = 0.5921/(-0.0022571) = -262.328

Standard enthalpy of reaction

dHo = -slope x R = -(-262.328 x 8.314) = 2180.995 J/mol

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