Part A Use the table of standard reduction potentials given above to calculate t

Question

Part A

Use the table of standard reduction potentials given above to calculate the equilibrium constant at standard temperature (25 C) for the following reaction:

Fe(s)+Ni2+(aq)Fe2+(aq)+Ni(s)

Express your answer numerically.

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Part B

Calculate the standard cell potential (E) for the reaction

X(s)+Y+(aq)X+(aq)+Y(s)

if K = 7.63×103.

Express your answer to three significant figures and include the appropriate units.

Reduction half-reaction E (V) Ag+(aq)+eAg(s) 0.80 Cu2+(aq)+2eCu(s) 0.34 Sn4+(aq)+4eSn(s) 0.15 2H+(aq)+2eH2(g) 0 Ni2+(aq)+2eNi(s) 0.26 Fe2+(aq)+2eFe(s) 0.45 Zn2+(aq)+2eZn(s) 0.76 Al3+(aq)+3eAl(s) 1.66 Mg2+(aq)+2eMg(s) 2.37

Explanation / Answer

A.

E|cell = E-Ni - E-Fe

E°cell = -0.26 - -0.45

E°cell = 0.19

b.

Apply

RT*lnK = nF*E°cell

E°cell = RT/(nF)*lnK

E°cell = 8.314*298/(1*96500)*ln(7.63*10^-3) = -0.1251 V

negative since K < 1

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