Formula for: 1) tetraamminecarbonatocobalt (III) sulfate 2) dichlorobis(ethylene

Question

Formula for: 1) tetraamminecarbonatocobalt (III) sulfate
2) dichlorobis(ethylenediamine)platinum (IV) bromide
3) potassium diaquatetrabromovanadate (III)
4) bis(ethylenediamine)zinc(II) teyraiodomercurate (II) Formula for: 1) tetraamminecarbonatocobalt (III) sulfate
2) dichlorobis(ethylenediamine)platinum (IV) bromide
3) potassium diaquatetrabromovanadate (III)
4) bis(ethylenediamine)zinc(II) teyraiodomercurate (II) 1) tetraamminecarbonatocobalt (III) sulfate
2) dichlorobis(ethylenediamine)platinum (IV) bromide
3) potassium diaquatetrabromovanadate (III)
4) bis(ethylenediamine)zinc(II) teyraiodomercurate (II)

Explanation / Answer

1)

the steps to get the formula are

a) find the central metal atom

in this case

it is Co+3

b)

now tetraammine

so

there are 4 NH3 groups

and

1 carbonate group

so

we get

Co(NH3)4(C03)]

now

we know that

C03 has -2 charge

and

Co has +3 charge

so

overall charge of Co(NH3)4(C03)] is 3-2 = 1

now

S04 has -2 charge

so

the formula should be

[Co(CO3)(NH3)4]2SO4

2)

similarly

[Pt(en)2Cl2]Br2

3)

K[V(H2O)2Br4]

4)

[Zn(en)2][HgI4]

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