Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Please help! For [H3O+] = 0.0015 M, determine the pH For [H3O+] = 8.8 x 10 ^-12

ID: 991978 • Letter: P

Question

Please help!
For [H3O+] = 0.0015 M, determine the pH
For [H3O+] = 8.8 x 10 ^-12 M, determine the pH

For [H3O+] = 9.6 x 10^-9 M, determine the pH

For [H3O+] = 0.0795 M, determine the pH

Please help!
For [H3O+] = 0.0015 M, determine the pH
For [H3O+] = 8.8 x 10 ^-12 M, determine the pH

For [H3O+] = 9.6 x 10^-9 M, determine the pH

For [H3O+] = 0.0795 M, determine the pH

Please help!
For [H3O+] = 0.0015 M, determine the pH
For [H3O+] = 8.8 x 10 ^-12 M, determine the pH

For [H3O+] = 9.6 x 10^-9 M, determine the pH

For [H3O+] = 0.0795 M, determine the pH

For [H3O+] = 8.8 x 10 ^-12 M, determine the pH

For [H3O+] = 9.6 x 10^-9 M, determine the pH

For [H3O+] = 0.0795 M, determine the pH

For [H3O+] = 9.6 x 10^-9 M, determine the pH

For [H3O+] = 0.0795 M, determine the pH

For [H3O+] = 0.0795 M, determine the pH

Explanation / Answer

[H3O+] = 0.0015 M

PH = -log[H3O+]

       = -log0.0015

PH = 2.82

2. [H3O+] = 8.8 x 10 ^-12 M

PH = -log8.8 x 10 ^-12

       = -log8.8 + 12log10

      = -0.9444 + 12 = 11.0556

[H3O+] = 9.6 x 10^-9 M

PH = -log9.6*10-9

      = -log9.6 + 9log10

    = -0.9822 +9 = 8.0178

4.[H3O+] = 0.0795 M

PH = -log0.0795

    = 1.099

3.