Calculait deltaGdegree for the reaction below a: 25degreeC Which of the followin
ID: 993377 • Letter: C
Question
Calculait deltaGdegree for the reaction below a: 25degreeC Which of the following it true if delta 6degree for a reaction is greater than zero? The value of the equilibrium constant for a pabular reaction Is 0.48 at 25degreeC What is the value of delta Gdegree In kJ for the reaction at 25degreeC Which one of the following is not zero for an element in its standard state at 25degreeC' Assuming degree H and deltaS do not vary with temperature, a reaction that is not spontaneous at low temperature can become spontaneous at high temperature if AH is and deltaS is The following react on is endothermic: 30_2(g) rightarrow 20_3(g). The reaction is...Explanation / Answer
7) 2SO2(g) + O2(g) ------> 2SO3(g)
delta Hrxn = 2*delta Hf SO3 - delta Hf O2 - 2*delta Hf SO2 = -196 kJ
delta Srxn = 2*delta Sf SO3 - delta Sf O2 - 2*delta Sf SO2 = -191 J/K
Now, delta Grxn = delta H - T*delta S = -196000 - 298*(-191) = -139082 J = -139.08 kJ
8) If delta G0 > 0 , the reaction is non-spontaneous. and hence K = 0
9) delta G0 = -R*T*lnK
or, delta G0 = -8.314*298*ln0.48 = 1818.4 J = 1.818 kJ
10) delta G0f is non-zero at standard state.
12) Since the reaction is endothermic, delta H > 0
Also, the moles of the gases are decraesing as the reaction proceeds, therefore delta S < 0
Now, delta G = delta H - T*delta S
Thus, at all temperatures,, delta G > 0
Hence the reaction is non-spontaneous at all temperatures.
The, correct option is :- (b)