Consider a solution containing 3.77 mM of an analyte, X, and 1.26 mM of a standa

Question

Consider a solution containing 3.77 mM of an analyte, X, and 1.26 mM of a standard, S. Upon chromatographic separation of the solution peak areas for X and S are 3807 and 10117, respectively. Determine the response factor for X relative to S. determine the concentration of X in an unknown solution, 1.00 mL of 8.89 mM S was added to 3.00 mL of the unknown X solution and the mixture was diluted to 10.0 mL. After chromatographic separation, this solution gave peak areas of 5319 and 4587 for X and S, respectively. Determine the concentration of S in the 10.0 mL solution. Determine the concentration of X in the 10.0 mL solution.

Explanation / Answer

the response factor is given by

F = Ax * [S] / As x [X]

using given values

we get

F = 3807 x 1.26 / 10117 x 3.77

F = 0.125765

so

the response factor is 0.125765

2)

we know that

for dilution

M1 x V1 = M2 x V2

so

for S

8.89 x 1 = M2 x 10

M2 = 0.889 mM

so

concentration of S in the 10 ml solution is 0.889 mM

3)

response factor is given by

F = Ax * [S] / As x [X]

given

Ax = 5319

As = 4587

[S] = 0.889 mM

so

0.125765 = 5319 x 0.889 / 4587 x [X]

[X] = 8.19677 mM

so

the concentration of [X] in the 10 ml solution is 8.19677 mM

5)

now

for X

M1 x V1 = M2x V2

M1 x 3 = 8.19677 x 10

M1 = 27.322 mM

so

concentration of X in the unknown solution is 27.322 mM

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