In a solution prepared by mixing 10.0 mL of 0.100 M Mg 2+ with 10.0 mL of 0.100
ID: 998196 • Letter: I
Question
In a solution prepared by mixing 10.0 mL of 0.100 M Mg 2+ with 10.0 mL of 0.100 M PO4^3- What is the concentration of Mg 2+ and PO4^3-. You must use the equation M1V1=M2V2
This is the entire question I do not need the whole thing solved I Justed need to know how to obtain the inital concentrations using the formula M1V1=M2V2
10. 12 pts) Consider the following reaction: s(PQ),(s) 3Mg"(aq) + 2P0;-(aq) Ksp = 1.0×10-13 What is the concentration of Mg2 and PO, in a solution prepared by mixing 10.0 mL of 0.100 M Mg2 with 10.0 mL of 0.100 M PO.. A precipitate forms.Explanation / Answer
since both Mg2+ and PO42- 0.1M before making the solution, which lead dilution of both anion and cation by half of its initial concentration.
M1V1 = M2V2
O.1M * 10ml = M2 * 20ml
M2 = 0.05 M ( both Mg2+ and PO42- initial concentrations.)