A sample of 7.77 g of liquid 1-propanol, C_3H_80, is combusted with 25.5 g of ox

Question

A sample of 7.77 g of liquid 1-propanol, C_3H_80, is combusted with 25.5 g of oxygen gas. Carbon dioxide and water are the products. Enter the balanced chemical equation for the reaction. Physical states are optional and not graded. Tip: If you need to clear your work and reset the equation, click the button that looks like two arrows. What is the limiting reactant? 1-propanol oxygen How many grams of CO_2 are released in the reaction? How many grams of the excess reactant remain after the reaction is complete?

Explanation / Answer

2C3H8O + 9 O2 ---------------------> 6CO2 + 8 H2O

120g              288 g                            264 g         144g

7.77g              25.5g

limiting reagnet = 1-propanol

120 g ------------> 264 g CO2

7.77 g -------------> x g CO2

x = 7.77 x 264 / 120

x = 17.1 g

CO2 mass = 17.1 g

120 g propanol ------------->288 g O2

7.77 g propanol needs -----------> 7.77 x 288 / 120 = 18.65 g

mass of excess reactant = 25.5 - 18.65

                                           = 6.85 g

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