Please help! And specify exactly as the directions are asking. Thank you in adva

Question

Please help! And specify exactly as the directions are asking. Thank you in advance! Put answers on a separate sheet of paper. For each problem, be sure to specify what you are solving for and what item (HCI, water or solution) you are operating on. Use proper units and identifiers for methods and answers. 1. An aqueous solution of hydrochloric acid (HCl, molar mass 36.5 g/mol) has a density of 1.18 g/mL and is 37 % HCl by mass. The solvent is water (molar mass = 18.0 g/mol). Perform the calculations indicated below. A) the molality of HCl B) the mole fractions of HCI and water C) the molarity of HC 2 Do the reverse calculations for he previous problems by using your answers for each part. A) mass percent from molality of HCl B) mass percent from the mole fractions of HCl and water C) mass percent from the molarity of HCI

Explanation / Answer

1.

A. molality = (37/36.5)*(1000/63) = 16.1 m

B. molefraction of HCl = (37/36.5)/((37/36.5)+(63/18)) = 0.224

   molefraction of water = 1-0.224 = 0.776

c.

volume of solution = 100/1.18 = 84.74 ml

molarity =   (37/36.5)*(1000/84.74)   = 11.96 M

2. A) 16.1 mole HCl in 1 kg solvent

   mass of HCl = 16.1*36.5 = 587.65 grams

   mass of slovent = 1000 grams

%by mass = (587.65/(1000+587.65))*100 = 37%

c) 11.96 mol HCl in 1 Lit solution

mass of solution = 1000*1.18 = 1180 grams

mass of HCl = 11.96*36.5 = 436.54 grams

%by mass = (436.54/1180)*100 = 37%

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