Please help! And please show your work. I am really strugling with this section.
ID: 1496093 • Letter: P
Question
Please help! And please show your work. I am really strugling with this section. Thank you
Assuming the minimum speed must be at least equal to its uncertainty, what is the electron's minimum kinetic energy?
tem 11 Part A If an electron's position can be measured to a precision of 15 nm, what is the uncertainty in its speed? Express your answer to two significant figures and include the appropriate units Submit My Answers Give Up All attempts used; correct answer displayed Part B Assuming the minimum speed must be at least equal to its uncertainty, what is the electron's minimum kinetic energy? Express your answer using two significant figures. KE4.34. 10-42 Submit My Answers Give Up Incorrect, One attempt remaining, Try AgainExplanation / Answer
Uncertainty in Position * Uncertainty in Momentum = h/4*pi
Uncertainty in position is what you are looking for so let's leave this on the Left hand side and get everything else on the right.
Delta (x) = h/[4*pi*delta(p)]
Where delta x and delta p = uncertainty in position and uncertainty in momentum respectively
15e-9=6.67e-34/4*3.14*delta(p)
deltam*deltav=6.67e-34/4*3.14*15e=3.54034e-27
deltav=3.54034e-27/deltam=1.14e4 m/s= 1140 m/s
KE=0.5mv^2 =0.5*9.1e-31*1140^2=5.91e-25