Please help! I got one attempt remaining pOH of the solution The pOH of a soluti

Question

Please help! I got one attempt remaining

pOH of the solution The pOH of a solution is related to the OH ion concentration of the solution. The "p" scale is used to express concentrations that are very small in magnitude. The hydrogen ion concentration is expressed in terms of pH. The formula for pOH is analogous to that for pH: pOH =-log[OH ] Part C n the simulation, open the Custom mode. The beaker will be filled to the 0.50 L mark with a neutral solution. Set the pH to 3.80 by using the green arrows adjacent to the pH value indicated on the probe in the solution. Once you adjust the pH, note the corresponding OH ion concentration in M as given in the graphic on the left side of the simulation. Make sure to select the option "Concentration (mol/L)" above the graphic. Find the pOH of the solution. Express your answer numerically to two decimal places Hints POH

Explanation / Answer

pH + pOH = 14

pH = 3.80

3.80 + pOH =14

pOH = 14 - 3.80

        = 10.2

[OH-] = 10^-10.2

       

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---