Identify the highest energy electrons (s) in each of the orbital diagrams on the

Question

Identify the highest energy electrons (s) in each of the orbital diagrams on the previous page. Which set of quantum numbers could identify the highest energy electron (or one of the highest energy electrons) for each element? Each element may be used more than once, but each answer blank will have only one correct choice. A, B, C or D? Fluorine n = 4, l = 0, m_1 = 0, m_s = +1/2 Bromine n = 2, l = 0, m_1 = 0, m_s = -l/2 Calcium n = 4, l = 1, m_1 = 0, m_s = +l/2 D. None of these elements n = 3, l = 2, m_1 = -2, m_s = +1/2 n = 2, l = 1, m_1 = -1, m_s = -1/2 n = 4, l = l, m_1 = -l, m_s = -1/2 n = 4, l = 0, m_1 = 0, m_s = -1/2 n = 2, 1 = 1, m_1 = 0, m_s = +1/2 n= l, l = 0, m_1 = 0, m_s = -l/2

Explanation / Answer

Fluorine --> [He] 2s2 2p5

Bromine --> [Ar] 3d10 4s2 4p5

Calcium --> [Ar] 4s2

Clearly, it must be bromine atom

so..

highest energy is 4s2 and 4p5

so..

n = 4; l = 4-1 = 3

so this is "p", meaning l = 0,1,2 --> 2

n=4, l = 2

configuration is not present

so

choose

None of these elements

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