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Part B In an air-conditioned room at 19.0 C, a spherical balloon had the diamete

ID: 1072875 • Letter: P

Question

Part B

In an air-conditioned room at 19.0 C, a spherical balloon had the diameter of 50.0 cm. When taken outside on a hot summer day, the balloon expanded to 51.0 cm in diameter. What was the temperature outside? Assume that the balloon is a perfect sphere and that the pressure and number of moles of air molecules remains the same.

Express your answer numerically in degrees Celsius.

Part C

A cylinder with a movable piston contains 2.00 g of helium, He, at room temperature. More helium was added to the cylinder and the volume was adjusted so that the gas pressure remained the same. How many grams of helium were added to the cylinder if the volume was changed from 2.00 L to 3.30 L ? (The temperature was held constant.)

Express your answer numerically in grams.

V 3.00 L V-1.00 L

Explanation / Answer

part A

from boyles law

P1V1 = P2V2

1.95*3 = P2*1

P2 = final pressure = 5.85 atm

part B

diameter (a1)= 50 cm

initial volume of sphere = v1 = 4/3*Pi*(50/2)^3

final volume of sphere = v2 = 4/3*Pi*(51/2)^3

V1/T1 = V2/T2

   50/(19+273.15) = 51/(x+273.15)

x = temperature outside = T2 = 24.83 c

part C

no of mole of He present initially = n1 = 2/4 = 0.5 mole

no of mole of He present finally = n2 = ?

from avagadros law

   v1/n1 = v2/n2


2/0.5 = 3.3/n2

n2 = 0.825 mole

amount of helium were added = (0.825-0.5)*4 = 1.3 g