Constants| Periodic Table Part A There are several factors that affect the rate
ID: 1076687 • Letter: C
Question
Constants| Periodic Table Part A There are several factors that affect the rate of a reaction. These factors include temperature, activation energy, steric factors (orientation), and also collision frequency, which changes with concentration and phase. All the factors that affect reaction rate can be summarized in an equation called the Arrhenius equation A certain reaction has an activation energy of 63.0 kJ/mol and a frequency factor of A1 5.10x1012 Ms-1. What is the rate constant, k, of this reaction at 24.0 °C ? Express your answer with the appropriate units. Indicate the multiplication of units explicitly either with a multiplication dot (asterisk) or a dash. View Available Hint(s) where k is the rate constant, A is the frequency factor Ea is the activation energy, R-8.314 J/(mol. K) is the universal gas constant, and T is the absolute temperature. Figure Submit ous Answer 1 of1 X Incorrect; Try Again The linear form of the Arrhenius equation The Arrhenius equation can be rearranged to a form that resembles the equation for a straight line In k In k- TTL where y is In k, m is the slope or - image.(Figure 1) and b is the y-intercept or In A. The linearity of this equation is illustrated graphically in the I/TExplanation / Answer
According to Arrhenius equation -
k = Ae-Ea/RT
where , k = rate constant
Ea = Activation Energy = 63kJ/mol =63000J/mol (given)
A = frequency factor = 5.10*1012M-1s-1 (given)
R = Gas constant = 8.314J/mol.K
T = temperature in Kelvein = (24 + 273.15) K = 297.15K
Take natural log of Arrhenius equation -
lnk = lnA -Ea/RT
Putting the value of A,Ea,R and T we get -
lnk = ln(5.10*1012) - 63000/(8.314*297.15)
lnk = 29.26- 25.475
lnk = 3.785
k = 44.0356 M-1s-1