Point charges q 1=? 4.90nC and q 2=+ 4.90nC are separated by distance 3.50mm , f
ID: 1284007 • Letter: P
Question
Point charges q1=? 4.90nC and q2=+ 4.90nC are separated by distance 3.50mm , forming an electric dipole.
1.) Find the magnitude of the electric dipole moment.
Express your answer in coulomb meters to three significant figures.
2.) What is the direction of the electric dipole moment? (either a or b)
a. from q1 to q2
b. from q2 to q1
3.) The charges are in a uniform electric field whose direction makes an angle 36.6? with the line connecting the charges. What is the magnitude of this field if the torque exerted on the dipole has magnitude 7.30
Explanation / Answer
Point charges q1=- 4.90*10^-9 C and q2=+ 4.90*10^-9 C
Distance = 2a = 3.50*10^-3 m ,
1) The magnitude of electric dipole moment.=q*2a
The magnitude of electric dipole moment.=4.90*10^-9*3.50*10^-3
The magnitude of electric dipole moment.=1.715*10^-11 Cm
2)The direction of the electric dipole moment is from q1 to q2 (from negative to positive)
3) The charges are in a uniform electric field whose direction makes an angle of 36.6 degrees with the line connecting the charges.
The torque exerted on the dipole has magnitude 7.30