In the figure below, a charged particle (either an electron or a proton) is movi

Question

In the figure below, a charged particle (either an electron or a proton) is moving rightward between two parallel charged plates separated by distance d = 1.70 mm. The particle is speeding up from an initial speed of 3600 km/s at the left plate.

(b) What is its speed just as it reaches the plate at the right?

km/s

In the figure below, a charged particle (either an electron or a proton) is moving rightward between two parallel charged plates separated by distance d = 1.70 mm. The particle is speeding up from an initial speed of 3600 km/s at the left plate. (b) What is its speed just as it reaches the plate at the right? km/s

Explanation / Answer

The acceleration of particle will depend upon the mass of the particle. (electron oor proton)

Electric field = deltaV/d = (-50+70)/0.0017 =11764.7 V/m

Force experienced = qE = 1.6E-19*11764.7 = 1.88E-15 N

acceleration of electron (electron will move in the direction shown) = a=F/mass = 2.06E15 m/s2

Mass =9.1E-31 kg

V2=U2+2ad

U= 3600km /s d =0.0017m

V = 4468.1km/s

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---