In the figure below, a charged particle (we know it is either an electron or a p
ID: 2123983 • Letter: I
Question
In the figure below, a charged particle (we know it is either an electron or a
proton), held close to the right plate, is released from rest to speed up toward
the left plate. The plates are parallel and at a distance of 5 mm from each other.
The plate are held at potentials V1= +30 V and V2= -180 V.
(a) What is the direction of the electric field between the plates?
(b) Is the particle an electron or a proton?
(c) What is the magnitude of the electric field between the plates?
(d) Use conservation of energy to calculate the speed of the particle when it reaches
the left plate.
Explanation / Answer
A) if the right plate is positive,then the particle is proton..... drection of E is from right to left
or if right plate is negative it is the particle is electron............drection of E is from left to right
B)if the right plate is positive,then the particle is proton.....otherwise it is electron.........
C) E=dV/x=210/0.005=42*10^3 V/m....
D)(1/2)*m*v^2=q*dV........
v=20.05 *10^4 m/sfor proton......
v=8.58*10^6 m/s for electron