Please answer all the questions thoroughly and explain how you answered the ques

Question

Please answer all the questions thoroughly and explain how you answered the question. Answer all the questions.

5. One thin lens of focal length 5.0 cm. and one thin diverging lens of focal length 10.0 cm. are separated by 10.0 cm. An object is placed 7.5 cm. to the left of the first lens (converging lens). Find the position and magnification of the final image. (Draw a neat sketch of the problem).

6. Two thin converging lenses of focal lengths 10 cm. and 20 cm. are separated by 20 cm. An object is placed 15 cm. in front of the first lens. Find the position of the final image and magnification of the system.

Explanation / Answer

for converging lens

1/S1 + 1/S1' = 1/F

1/7.5 + 1/S1' = 1/5

S1' = (7.5*5)/(7.5-5) = 15 cm this real image will act like a object for second diverging lens

for diverging lens

S2 = 10-15 = -5 cm

1/S2 +1/S2 = 1/F2

-1/5 + 1/S2' = -1/10

S2' = 5 cm

M = (-S2'/S2)*(-S1'/S1)

M = (5/5)*(-15/7.5) = -2

the final image is real invertedt and larger

6)

for converging lens

1/S1 + 1/S1' = 1/F

1/15 + 1/S1' = 1/10

S1' = (15*10)/(15-10) = 30 cm this real image will act like a virtual object for second converging lens

for converging lens

S2 = 20-30 = -10 cm

1/S2 +1/S2 = 1/F2

-1/10 + 1/S2' = 1/20

S2' = 20/3 = 6.67 cm

M = (-S2'/S2)*(-S1'/S1)

M = (6.67/10)*(-30/15) = ?1.334

the final image is real inverted and larger

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