An object is placed in front of a mirror and an image is produced on a screen wh

Question

An object is placed in front of a mirror and an image is produced on a screen which has a magnification of -2.90 when the screen is placed 27.0cm from the mirror.

Part A

What type of mirror is being used?

Part B

If the original object is erect and 14 cm tall, how tall is the image on the screen?

Part C

What is the focal length of the mirror?

Part D

If the screen is moved to 35 cm away from the mirror, how far from the mirrors surface must the object be placed to get a clear image on the screen?

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Explanation / Answer

part A )

concave mirror

part B)

M = -2.9 = -s'/s = I/O

I = M*o = 2.9*14 = 40.6 cm

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part C)

given image distance s' = 27 cm

object distance s = s'/2.9 = 27/2.9 = 9.31 cm

1/s + 1/s' = 1/f

(1/9.31)+(1/27) = 1/f

f = 6.92 cm

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part D)

s1' = 35 cm

(1/s1) + (1/s1' ) = 1/f

1/s1 + (1/35) = (1/6.92)

s1 = 8.62 cm

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